Question

What is an equation for the line that passes through points (6, 9) and (5, 2)?

Answer 1

x = 6 y = 9
x1 = 5 y1 = 2

1. Find the slope
m = y - y1 / x - x1
m = 9 - 2 / 6 - 5
m = 7 / 1
m = 7

2. Point - Slope Formula
y - y1 = m (x - x1)
y - 2 = 7 (x - 5)
y - 2 = 7x - 35
y = 7x - 35 + 2
y = 7x - 33

Equation of the line: y = 7x - 33

Answer 2

First, we need to find the slope. We will use the slope formula:
`( y_(2) - y_(1) )/( x_(2) -x_(1) )`
9-2/6-5
7/1
The slope of the line is 7.
Next, we will use point-slope form.
y-y=m(x-x) Plug in the slope and one point.
y-2=7(x-5)
Simplfy
y-2=7x-35
y=7x-33