115k views
4 votes
What are the period and phase shift for f(x) = 5 tan(2x − π)?

Period: π; phase shift: x = pi over two
Period: π; phase shift: x = negative pi over two
Period: pi over two; phase shift: x = negative pi over two
Period: pi over two; phase shift: x = pi over two
I think it is A.. Please explain

User Diadyne
by
7.9k points

2 Answers

4 votes
period: pi/2; phase shift: x = -pi/2
User Bkomac
by
8.3k points
5 votes

Answer:

D.
\text{Period}=(\pi)/(2); Phase shift
x=(\pi)/(2)

Explanation:

We have been given a function
f(x)=5\text{ tan}(2x-\pi). We are asked to find the period and phase shift for the given function.

We will use formula
f(x)=a\cdot \text{tan}(bx-c)+d, where,

a = Amplitude,


\text{Period}=(\pi)/(|b|)


\text{Phase shift}=(c)/(b)

d = Vertical shift.

Upon substituting the given values we will get period of the given function as:


\text{Period}=(\pi)/(|2|)=(\pi)/(2)

We can find phase shift for our given function as:


x=(\pi)/(2)

Therefore, option D is the correct choice.

User Mayette
by
8.5k points