Question

Use the slope-intercept form to graph the equation 2x - 5y = - 15.

Answer 1

To do this, this equation must be taken to the form

`\begin{gathered} y=mx+b \\ \text{Where} \\ m\colon\text{Slope oth the line} \\ b\colon\text{ intercept with the y-axis} \end{gathered}`

So,

`\begin{gathered} 2x-5y=-15 \\ \text{ Substract 2x from both sides of the equation} \\ 2x-5y-2x=-15-2x \\ -5y=-15-2x \\ \text{Divide by -5 from both sides of the equation} \\ (-5y)/(-5)=(-15)/(-5)-(2)/(-5)x \\ y=3+(2)/(5)x \\ y=(2)/(5)x+3 \end{gathered}`

Then a positive slope of 2/5 tells you that for every 2 units on the y-axis there are 5 units on the x-axis. And 3 tells you that the line intercepts the y-axis at 3.