How many atoms and molecules are present in 124 gram of phosphorus

asked May 17, 2018 46.4k views

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31g phosphorus has 6.02×10^23 atoms
then 124 " '' (6.02×10^23×124)÷31
≈2.408×10^24
and molecules are (2.408×10^24×2)
≈4.816×10^24

Necixy answered May 24, 2018

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