Remember that
Mutually Exclusive ------> can't happen at the same time
In this problem
these events are not mutually exclusive
because
the sum of their probabilities is greater than 100%
the formula to calculate the probability is equal to
P(A or B) = P(A) + P(B) − P(A and B)
Let
event A -----> students own a computer
event B -----> students own a phone
32% 0f 25 students ------> 8
98% of 25 students -----> 24.5=25
that means
8 students have a computer and a phone
Part 1
What is the probability that a student owns a phone and does not own a computer?
total students=25
the total student that owns a phone and does not own a computer=17 students
P=17/25
Part 2
What are the odds that a random student that is selected will be the owner of a computer and a phone?
the odds are equal to
8:17
Part 3
How many students would you expect to own both a computer and a phone?
8 students