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5 votes
Please help me figure this out

Please help me figure this out-example-1

2 Answers

3 votes
notice the picture below

thus, using the "far arc - near arc" theorem
\bf \measuredangle A=\cfrac{\widehat{BDC}-\widehat{BC}}{2}

now, we know what arcBC is, what's arcBDC? well, keep in mind, a circle only has 360°, so if arcBDC is just 360 - arcBC
Please help me figure this out-example-1
User Kirill Ermolov
by
8.2k points
4 votes
By my calculations it is about 104
User Eben Kadile
by
8.0k points

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