Please help me figure this out

Question

asked May 27, 2018 86.9k views

2 Answers

Kirill Ermolov · Answer 1 · 2018-05-29T08:06:05+0000

notice the picture below

thus, using the "far arc - near arc" theorem
$\bf \measuredangle A=\cfrac{\widehat{BDC}-\widehat{BC}}{2}$

now, we know what arcBC is, what's arcBDC? well, keep in mind, a circle only has 360°, so if arcBDC is just 360 - arcBC

Please help me figure this out-example-1

Please help me figure this out

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

No related questions found

Other Questions