Question

Round to the nearest tenth.-3.9x + 2 = 7x + 1

Answer 1

`\begin{gathered} \text{ To begin with we sum 3.9x on both sides of the equality } \\ -3.9x+3.9x+2=7x+3.9x+1 \\ 2=10.9x+1 \\ \text{Now we add -1 on both sides of the equation } \\ 2-1=10.9x+1-1 \\ \text{After that we will have cancelled 1, and we get } \\ 1=10.9x \\ Then\text{ we divide by 10.9 on both sides of the equation and get } \\ 1/10.9=10.9x/10.9 \\ \text{And we will have cancelled 10.9, which solves the problem. } \\ 1/10.9=x \\ And\text{ we get } \\ x=0.091743 \\ \text{ Since we need to round to the nearest tenth we get } \\ x=0.1 \end{gathered}`