Question

Twice the smallest of three consecutive even integers is twelve more than the largest. Find the integers.

Answer 1

16, 18 and 20

Step-by-step explanation

Let the first number be x.

The next consecutive even number will be x + 2

The third consecutive even number will be x + 4

So, twice the smallest of three consecutive even numbers is twelve more than the largest.

That is:

2*x = 12 + x + 4

=> 2x = 12 + x + 4

Collect like terms:

2x - x = 12 + 4 = 16

x = 16

Therefore, the three consecutive even numbers are:

16;

16 + 2 = 18;

16 + 4 = 20.