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Write the quadratic equation in general form. what is the value of b 2 - 4ac? 1 = 2x 2 7x 40 41 57

User Dummzeuch
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1 Answer

5 votes

Answer:


2x^2+7x-1= 0


b^2-4ac = 57

Explanation:

The general form of the quadratic equation is:


ax^2+bx+c = 0 ....[1]

Given the equation:


1 = 2x^2+7x

Subtract 1 from both sides we have;


0= 2x^2+7x-1

or we can write this as:


2x^2+7x-1= 0

We have to find the
b^2-4ac

Compare equation
2x^2+7x-1= 0 with equation [1]

a = 2 , b = 7 and c = -1

then;


b^2-4ac = (7)^2-4(2)(-1) = 49+8 = 57

Therefore, the quadratic equation in general form is,
2x^2+7x-1= 0 and the value of
b^2-4ac is, 57

User Mpm
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