Question

Of the 120 families, approximately___pay more than $5710 annually for day car per child.

Answer 1

1) Considering a Normal Distribution, then we can write out the following:

`P(X>5710)=P(X-\mu>5710-6000)=P((X-\mu)/(\sigma)>(5710-6000)/(1000))`

Note that we're dealing with probabilities.

2) Let's find out the Z-score resorting to a table, we get:

`Z=(x-\mu)/(\sigma)=(5710-6000)/(1000)=-0.29`

2.2) So we can infer from 1 and 2:

`P(X>5710)=P(Z>-0.29)=0.6141`

Notice that this distribution refers to 120 families