ANSWER :
The answer is :
0.8369
EXPLANATION :
From the problem, we have :
[tex]P(-2.62We need to get the area under the curve between z = -2.62 and z = 1
Using the normal distribution table which indicates an area under the curve to the left of the given negative z.
and the other one is the positive z.
So if we subtract the areas under the two curves. we will get the area between the two z's.
That will be :
[tex]P(-2.62Use the table to find the values of P(z < 1) and P(z < -2.62)
That will be :
Look for the value of z = 1.0, and that is 0.8413
The other value is at z = -2.62 :
and that is 0.0044
Get the difference between the two.
[tex]\begin{gathered} P(-2.62