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Solve the system using elimination 2x+2y=62x-2y=6

User Rhalp Darren Cabrera
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1 Answer

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29 votes

Given the system of equations:


\begin{gathered} 2x+2y=6 \\ 2x-2y=6 \end{gathered}

we can solve it using elimination by directly adding both equations to get the following:


\begin{gathered} 2x+2y=6 \\ 2x-2y=6 \\ ---------- \\ 4x=12 \\ \Rightarrow x=(12)/(4)=3 \\ x=3 \end{gathered}

now that we have that x=3, we can find y using this value on any of the two equations:


\begin{gathered} 2x+2y=6 \\ x=3 \\ \Rightarrow2(3)+2y=6 \\ \Rightarrow6+2y=6 \\ \Rightarrow2y=6-6=0 \\ \Rightarrow2y=0 \\ y=0 \end{gathered}

therefore, the solution of the system is (3,0)

User Fred Laurent
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