Question

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Answer 1

`\begin{gathered} (2x^3-13x^2+9x-16)/(x-6) \\ \end{gathered}`

From the division result above,

The quotient is

`2x^2-x+3`

While the remainder is 2

The result of the division can be written in the form

`(2x^2-x+3)\text{ +}(2)/(x-6)`

The answer is

`(2x^3-13x^2+9x-16)/(x-6)=\text{ }(2x^2-x+3)\text{ +}(2)/(x-6)`