a = 10 - 5(n-1) (option C)
Step-by-step explanation:
we need to check theoptions to determine the one that gives the sequence
sequence 10,5, 0, -5, ... = T1, T2, T3, ........
A) a = -10 - 5(n-1)
when n = 1
a = -10 - 5(1-1) = -10-5(0)
a = -10 -0 = -10
This option is wrong because our T1 = 10
B) a = -5n + 10(n-1)
when n = 1
a = -5(1) + 10(1-1)
a = -5+10(0) = -5 + 0 = -5
This option is wrong because our T1 = 10
C) a = 10 - 5(n-1)
when n = 1
a = 10 - 5(1-1) = 10-5(0)
a = 10 - 0 = 10
we ned to confirm:
when n = 2
a = 10-5(2-1) = 10-5(1) = 10-5 = 5
This option is correct. T1 = 10, T2 = 5
D) a = -10n - 5(n-1)
when n = 1
a = -10(1) - 5(1-1)
a = -10 -0 = -10
This option is wrong because our T1 = 10
the equations can be used to create the sequence is a = 10 - 5(n-1) (option C)
b)