Answer:
The two integers are 5 and 14
Explanations:
Let the two integers be x and y
An integer is 6 less than 4 times another
x = 4y - 6.............(1)
The product of the two integers is 70
xy = 70.............(2)
Substitute equation (1) into equation (2)
(4y-6)y = 70
4y² - 6y - 70 = 0
Divide through by 2, the equation becomes:
2y² - 3y - 35 = 0
2y² - 10y + 7y - 35 = 0
2y(y - 5) + 7(y - 5) = 0
(y - 5) (2y + 7) = 0
y - 5 = 0
y = 5
2y + 7 = 0
2y = -7
y = -7/2 (This is not possible since only integer values are expected)
Substitute y = 5 into equation (1)
x = 4y - 6
x = 4(5) - 6
x = 20 - 6
x = 14
The two integers are 5 and 14