Question

How to solve for a and b

Answer 1

`\bf \begin{cases} 3=a\cdot b^0\\ 75=a\cdot b^2 \end{cases}\qquad b^0=1\implies \begin{cases} 3=a\cdot 1\implies 3=a\\ ----------\\ 75=a\cdot b^2\implies 75=3\cdot b^2\\\\ (75)/(3)=b^2\implies 25=b^2\\\\ \pm √(25)=b\implies \pm 5 = b \end{cases}`

recall, anything raised to the 0, zero, power, is 1, with the sole exception of 0