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How much money should be deposited today in an account that earns 9.5% compound education monthly so that it will accumulate to $10,000 in one and half year?

User Dpndra
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\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+(r)/(n)\right)^(nt) \quad \begin{cases} A=\textit{compounded amount}\to &\$10000\\ P=\textit{original amount deposited}\\ r=rate\to 9.5\%\to (9.5)/(100)\to &0.095\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus} \end{array}\to &12\\ t=years\to &(3)/(2) \end{cases}

notice, the years are one and a half, or 3/2

solve for P, to see what the Principal should be
User Nikola Knezevic
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