Question

A 2.61 kg block slides DOWN a 15.0°incline withMk = 0.220What is its acceleration?(Unit=m/s^2)

Answer 1

Given

Mass is m=2.61 kg

Angle is

`\theta=15^o`

Coefficient of friction is,

`\mu_k=0.22`

To find

The acceleration of the block

Step-by-step explanation

The free body diagram is

Thus at equilibrium,

`\begin{gathered} ma=mgsin15-f \\ ma=mgsin15-\mu_kmgcos15 \\ \Rightarrow a=9.8sin15-0.22*9.8cos15 \\ \Rightarrow a=0.45\text{ m/s}^2 \end{gathered}`

Conclusion

The acceleration is

`0.45\text{ m/s}^2`