Question

A 65 ml sample of argon gas has a temperature of 325 °c. what will the temperature be in °c when the volume of the gas is decreased to 25 ml at constant pressure?

Answer 1

Answer:
`-43^(\circ) C`

Step-by-step explanation:

We can solve the problem by using Charle's law, which states that for a gas at constant pressure, the volume V and the absolute temperature of the gas T are directly proportional. In formulas:

`(V_1)/(T_1)=(V_2)/(T_2)`

where

`V_1 = 65 mL=0.065 L` is the initial volume

`T_1 = 325 C=598 K` is the initial temperature

`V_2 = 25 mL=0.025 L` is the final volume

`T_2` is the final temperature

By solving the equation,

`T_2 = T_1 (V_2)/(V_1)=(598 K)(0.025 L)/(0.065 L)=230 K`

In Celsius, the final temperature is

`T_2 = 230 K-273 = -43^(\circ) C`