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What is the perimeter of a rectangle with the width equal to 45 feet and a length twice as long as the width? A. 270 feet B. 180 feet C. 135 feet D. 2025 feet
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4 votes
What is the perimeter of a rectangle with the width equal to 45 feet and a length twice as long as the width?

A. 270 feet
B. 180 feet
C. 135 feet
D. 2025 feet

User Ian Hopkinson
by
7.6k points

2 Answers

4 votes
You would do 45*2 to find the length, which would be 90.

Perimeter is length+length+width+width.

So it would be 45+45+90+90

the answer is A. 270
User DMML
by
7.6k points
5 votes
A) 270 feet  two time 45 feet is 90 and 90+90+45+45=270
User Hamza Dahmoun
by
8.2k points
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