Question

PLEASE HELP!!!!

Solve logx + 5 36 = 2.
options:
x=1
x=11
x=13
x=23
ok so I think it may be 13 or 23 but I'm not sure which. Any ideas?

Answer 1

if x+5 is the base, the equation means (x+5)^2=36

clearly x+5=6

hence x=1

Answer 2

`\displaystyle\\ \bf\\ log_(x+5) 36 = 2\\\\ \Longrightarrow~~(x+5)^2 = 36\\\\ (x+5)^2 = 6^2\\\\ x+5= 6\\\\ x = 6 - 5 = \boxed{\bold{1}}`