Question

The smallest of three consecutive integers is 15 less than the sum of two larger integers find the three integers

Answer 1

Given

The smallest of three consecutive integers is 15 less than the sum of two larger integers.

To find the three integers.

Step-by-step explanation:

It is given that,

The smallest of three consecutive integers is 15 less than the sum of two larger integers.

Let x be the smallest integer.

That implies, x, (x+1), (x+2) are the three consecutive integers.

Since the smallest of the three consecutive integers is 15 less than the sum of the two larger integers.

Then,

`\begin{gathered} x=[(x+1)+(x+2)]-15 \\ x=x+x+3-15 \\ x=2x-12 \\ 2x-x=12 \\ x=12 \end{gathered}`

Hence, the three integers are 12, 13, 14.