Question

1.Calculate the molarity of a 1.5 L solution that contains 0.24 mol HCL2.State the mass of the solute required to prepare 1.00 L of 2,5 M NH4Cl solution.3.State the mass of the solute required to prepare 4.00 L of 0.55 M Hg(NO3)2 solution.4.Calculate the molarity of a 3.5 L that contains 2.8 mol of HNO3.5.State the mass of the solute required to prepare 125 mL of 0.25 M Ba(NO3)2 solution.6.Calculate the concentration of a 60,0 mL solution that contains 0.075 mol of NH4Cl.7.Calculate the molarity of a 400.0 mL solution that contains 41.5 g of NaCl.8. What volume of 1.50 M KCl can be made from 550 g of KCI.9.Calculate the concentration of a 600.0 mL solution that contains 2.50 g of CaCO3.10. State the mass of the solute required to prepare 325 mL of a 1.5 M CuSO4.5 H2O solution.11. Calculate the molarity of a 200 mL solution that contains 1.2 x 1024 molecules of NaOH.12.How many moles of Cu(NO3)2 are contained in 400.0 mL of 0.90 M Cu(NO3)2.13. A 250.0 mL sample of 0.10 M Na2SO4 is evaporated to dryness. The resulting solid is thenweighed. What mass of solute would be recovered from the solution?

Answer 1

0.16M

Explanations:

The formula for calculating the molarity of a substance is expressed as;

`molarity=(mole)/(volume)`

Given the following parameters

• mole of HCl = 0.24 mol

,

• volume of the solution = 1.5L

Substitute the given parameters into the formula to have:

`\begin{gathered} molarity=(0.24mol)/(1.5L) \\ molarity=0.16mol\text{/L} \end{gathered}`

Therefore the molarity of the solution is 0.16M