Question

Can someone help me know what to do with this?

Answer 1

we have the following

`2x+3y=6`

we can write in slope-intercept form as it follows

`\begin{gathered} 2x+3y=6 \\ 3y=6-2x \\ (3y)/(3)=(6)/(3)-(2)/(3)x \\ y=2-(2)/(3)x \\ y=-(2)/(3)x+2 \end{gathered}`

The slope-intercept form is y = mx + b , where:

Slope m = -2/3

y-intercept b = 2

therefore, the vertical intercept is (0,2)

To find the horizontal intercept, we replace y = 0

`\begin{gathered} 2x+3y=6 \\ 2x+0=6 \\ 2x=6 \\ x=(6)/(2) \\ x=3 \end{gathered}`

therefore the horizontal intercept is (3,0)

Finally, to graph we must locate the two points obtained, that is, the vertical intercept (0,2) and the horizontal intercept (3,0) and join them with a straight line