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A game wheel has 38 slots numbered 1-38, respectively. Matt places a bet on the odd numbers and Julie places a bet on numbers 10, 11, 13, and 14. What is the probability of landing on an odd number or 10, 11, 13, or 14? Show all work.

1. 2/3
2. 19//38
3. 9/19
4. 21/38

1 Answer

3 votes
Odd numbers are of the from a(n)=a+d(n-1) where a=1 and d=2 so

a(n)=1+2(n-1)=2n-1 and we need the number of odds in the range 1 to 38

2n-1≤38

2n≤39

n≤19.5, so there are 19 odd numbers in [1,38]

And since Julie bet on two even numbers as well, the probability of getting an odd number or the two evens she picked is:

(19+2)/38

21/38


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