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I NEED step by step help with : 4x^2(x-1)^(1/3) + 6x(x-1)^(4/3) =0.

User Dugan
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1 Answer

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divide the whole equation by (x-1)^(1/3) and you get:

4x^2+6x(x-1)^(3/3)=0 which is equal to:

4x^2+6x(x-1)=0 which is equal to:

4x^2+6x^2+6x=0

10x^2+6x=0 factor...

2x(5x+3)=0

So there are two solutions:

x=-3/5 and 0
User Jorgehmv
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