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If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found by dividing area by length?

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24a2b can be rewritten as 48ab and 8ab2 can be rewritten as 16ab to make it simpler later on. Now we have the Area(48ab) and Length(16ab).
Width=(48ab)/(16ab).
Both 48 and 16 can be divided by 16 thus simplifying to (3ab)/(ab) The ab's cancel each other out or equal one when divided.

We are then left with the answer 3 for the width of the garden.
User Anatol
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