Question

What is the perimeter, in terms of x, of the triangle shown here?

(7x2 - 12)
(-5x + 30)
(3x2 + 4x)

Answer 1

The perimeter of triangle is:
`\mathbf{10x^2-x+18}`

Explanation:

We need to find perimeter, in terms of x, of the triangle shown here.

The length of side 1:
`(7x^2 - 12)`

The length of side 2:
`(-5x + 30)`

The length of side 3:
`(3x^2 + 4x)`

The formula used to find perimeter of triangle is:
`Perimeter\: of\: triangle=Sum\:of\:length\:of\:all\:sides`

Putting values and finding perimeter:

`Perimeter\: of\: triangle=Sum\:of\:length\:of\:all\:sides\\Perimeter\: of\: triangle=(7x^2 - 12)+(-5x + 30)+(3x^2 + 4x)\\Perimeter\: of\: triangle= 7x^2-12-5x+30+3x^2+4x\\Perimeter\: of\: triangle=7x^2+3x^2-5x+4x-12+30\\Perimeter\: of\: triangle=10x^2-x+18`

So, The perimeter of triangle is:
`\mathbf{10x^2-x+18}`