Question

A 200 gram sample of metal is warmed from 50°C to 80°C when 100 calories of heat are added. What is he specific heat capacity of the metal?

Answer 1

Given:

The mass of the sample is

`m=200\text{ g}`

The initial temperature is

`t_i=50\text{ }\degree C`

The final temperature is

`t_f=80\text{ }\degree C`

The amount of heat is,

`H=100\text{ cal}`

To find:

The specific heat capacity of the metal

Step-by-step explanation:

Let the specific heat capacity is 'c'

The amount of heat for the temperature change is,

`H=mc(t_f-t_i)`

Substituting the values we get,

`\begin{gathered} 100=200* c*(80-50) \\ 100=200* c*30 \\ c=(100)/(200*30) \\ c=0.016\text{ cal/g.}\degree C \end{gathered}`

Hence, the specific heat capacity is

`0.016\text{ cal/g.}\degree C`