97.3k views
5 votes
Calculate the number of particles of 285 grams of iron (III) oxide.

User Allister
by
6.3k points

1 Answer

2 votes
Using Avogadro's Number and stoichiometry:

285 g Fe2O3 x (1 mol Fe2O3/159.7 g Fe2O3) x (6.022x10^23 particles/1 mole) = 1.07x10^24 particles of Fe2O3
User Gleichmut
by
6.4k points