We have a bag that contains:
• 6 red pieces of candy,
,
• 45 pieces of candy in total.
We have the following individual events:
• E_1 = randomly we draw and eat a red candy from the bag,
,
• E_2 = randomly we draw and eat a second red candy from the bag.
To happen event E_2, first, it must happen the first event E_1. So the events are dependent.
Let's compute the probability of the combined event.
1) The probability of drawing the first red candy is:
P(1st red candy) = 6/45
2) The probability of drawing a red candy after the 1st red candy is:
P(2nd red candy after the 1st red candy) = 5/44
3) The probability of drawing 2 red candies in a row is:
P(2nd red candy after 1st red candy) = P(1st red candy) * P(2nd red candy after the 1st red candy) = 6/45 * 5/44 = 1/66
Answer
The individual events are dependent, the probability of the combined event is 1/66.