Question

An equation that defined y as a dun6of x is given.

Answer 1

Step-by-step explanation:
`\begin{gathered} Given: \\ 5x\text{ - 6y = 5} \\ \\ We\text{ will make y the subject of formula by performing some operations} \end{gathered}`

subtract 5x from both sides of the equation:

`\begin{gathered} 5x\text{ - 5x - 6y = 5 - 5x} \\ 0\text{ - 6y = 5 - 5x} \\ -6y\text{ = 5 - 5x} \end{gathered}`

Divide both sides by -6:

`\begin{gathered} (-6y)/(-6)\text{ = }\frac{5\text{ - 5x}}{-6} \\ y\text{ = }\frac{5\text{-5x}}{-6} \end{gathered}`

The question asked that we replace y with f(x):

`f(x)\text{ = }\frac{5\text{ - 5x}}{-6}\text{ \lparen3rd option\rparen}`