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Find the scalar and vector projections of b onto a.a =(−3, 4)b =(7, 9)

User Emptyset
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1 Answer

22 votes
22 votes

Take into account that the scalar projection is given by:


comp_a\vec{b}=\frac{\vec{a}\cdot\vec{b}}{a}

the magnitude of a vector is:


\begin{gathered} a=\sqrt[]{(-3^{})^2+4^2} \\ a=\sqrt[]{25}=5 \end{gathered}

The dot product between a and b is:


\vec{a}\cdot\vec{b}=(-3,4)\cdot(7,9)=-3\cdot7+4\cdot9=-21+36=15

Then, the scalar projection is:


\text{comp}_a\vec{b}=(15)/(5)=3

Now, consider that the vector projections is given by:


\begin{gathered} \text{proj}_a\vec{b}=(\frac{\vec{a}\cdot\vec{b}}{a})(a)/(\lvert a\rvert) \\ \text{proj}_a\vec{b}=(3)/(5)\cdot(-3,4)=(-(9)/(5),(12)/(5)) \end{gathered}

Hence, the answer is:

scalar projection of b onto a = 3

vector projection of b onto a = (-9/5 . 12/5)

User Yurets
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