Question

PART A.Which family spends the smallest dollar amount on housing?Family AFamily BFamily CPART B.Which family spends the largest dollar amount on other needs?Family AFamily BFamily CPART C.Which family spends the largest dollar amount on transportation?Family AFamily BFamily C

Answer 1

Hello!

First, let's look at the image and write some important information about each family:

PART A.

Family A:

• Monthly Income: $5,400

,

• Housing Percentage: 19%

Family B:

• Monthly Income: $4,675

,

• Housing Percentage: 16%

Family C:

• Monthly Income: $6,675

,

• Housing Percentage: 14%

To solve this exercise, we must use the rule of three, look:

Family A: $1,026

`\begin{gathered} (5400\rightarrow100\%)/(x\rightarrow19\%) \\ \\ 100x=102,600 \\ x=(102,600)/(100)=1,026 \end{gathered}`

Family B: $748

`\begin{gathered} (4675\rightarrow100\%)/(x\rightarrow16\%) \\ \\ 100x=74,800 \\ x=(74,800)/(100)=748 \end{gathered}`

Family C: $934

`\begin{gathered} (6675\rightarrow100\%)/(x\rightarrow14\%) \\ \\ 100x=93,450 \\ x=(93,450)/(100)=934 \end{gathered}`

Answer:

Family B

PART B.

Family A:

• Monthly Income: $5,400

,

• Other Needs Percentage: 9%

Family B:

• Monthly Income: $4,675

,

• Other Needs Percentage: 7%

Family C:

• Monthly Income: $6,675

,

• Housing Percentage: 6%

Let's solve in a similar way as we did before:

Family A: $486

`\begin{gathered} (5400\rightarrow100\%)/(x\rightarrow9\%) \\ \\ 100x=48,600 \\ x=(48,600)/(100)=486 \end{gathered}`

Family B: $327.25

`\begin{gathered} (4675\rightarrow100\%)/(x\rightarrow7\%) \\ \\ 100x=32,725 \\ x=(32,725)/(100)=327.25 \end{gathered}`

Family C: $400.50

`\begin{gathered} (6675\rightarrow100\%)/(x\rightarrow6\%) \\ \\ 100x=40,050 \\ x=(40,050)/(100)=400.50 \end{gathered}`

Answer:

Family A.

PART C:

Family A:

• Monthly Income: $5,400

,

• Transportation Percentage: 11%

Family B:

• Monthly Income: $4,675

,

• Transportation Percentage: 13%

Family C:

• Monthly Income: $6,675

,

• Transportation Percentage: 9%

Let's solve:

Family A: $549

`\begin{gathered} (5400\rightarrow100\%)/(x\rightarrow11\%) \\ \\ 100x=59,400 \\ x=549 \end{gathered}`

Family B: $607.75

`\begin{gathered} (4675\rightarrow100\%)/(x\rightarrow13\%) \\ \\ 100x=60,775 \\ x=607.75 \end{gathered}`

Family C: $600.75

`\begin{gathered} (6675\rightarrow100\%)/(x\rightarrow9\%) \\ \\ 100x=60,075 \\ x=600.75 \end{gathered}`

Answer:

Family B.