Final answer:
In the given reaction, there are 1.8066 × 10²⁴ molecules of H₂, 6.022 × 10²³ nitrogen atoms, and 3.011 × 10²³ moles of NH₃ formed.
Step-by-step explanation:
The balanced equation for the reaction is:
N₂ + 3H₂ → 2NH₃
From the equation, we can determine the following:
- The number of molecules of H₂ represented in the reaction is 3 times the number of molecules of N₂. So, if we have 6.022 × 10²³ molecules of N₂, we would need 3 times that amount of H₂, which is 1.8066 × 10²⁴ molecules of H₂.
- The number of nitrogen atoms represented in the reactants is the same as the number of nitrogen molecules, which is 6.022 × 10²³ molecules of N₂.
- The number of moles of NH₃ formed is half the number of moles of N₂, since the reaction produces 2 moles of NH₃ for every 1 mole of N₂. Therefore, if we have 6.022 × 10²³ molecules of N₂, we would produce 3.011 × 10²³ moles of NH₃.