Question

What are the zeroes of y=x^2+14x+40

Answer 1

`y=x^2+14x+40`


`y-x^2-14x-40=0`

In general, given
`a{x}^(2)+bx+c=0`, there exists two solutions where


`x= (14+2 √(y+9) )/(-2) , (14-2 √(y+9) )/(-2)`


`x=-7- √(y+9),-7+ √(y+9)`