Question

How many milliliters of 10.5 M HCl(aq) are needed to prepare 795.0 mL of 1.00 M HCl(aq)?

Answer 1

To solve this we use this formula

M1 x V1 = M2 x V2

1 is for solution number 1

2 is for solution 2

Now, we need to clear V1

So, M1 x V1 = M2 x V2

V1 = M2 x V2 / M1 = 1.00 M x 795.0 mL / 10.5 M = 75.71 mL

Answer: V1 = 75.71 mL