Question

A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4 °F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5°F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation. Complete the steps below to solve the problem

Answer 1

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 =
63 - 2 = 61
1/4 - 1/5 = 5/20 - 4/20 = 1/20
so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F

Answer 2

At the elevation 617.5 feet below the sea level temperature of the water was
`61(1)/(20)`°F

Explanation:

At 502.5 feet below the sea level temperature of the water is
`63(1)/(4)`°F

When submarine dives down 115 feet deeper, water temperature drops by
`2(1)/(5)`°F

Elevation after the submarine dove = -502.5 - 115 = -617.5 feet

This negative sign represents the elevation below the sea level.

And the temperature will be =
`63(1)/(4)-2(1)/(5)`

=
`(253)/(4)-(11)/(5)`

=
`(1265-44)/(20)`

=
`(1221)/(20)`

=
`61(1)/(20)`°F

Therefore, at the elevation 617.5 feet below the sea level temperature of the water was
`61(1)/(20)`°F