Question

What is the center and radius of this circle.. (x-2) squared + (y-3) squared = 16

Answer 1

Our formula is:

`(x-2)^2 + (y-3)^2 = 16`
Which is in the general formula for a circle:

`(x-a)^2 + (y-b)^2 = r^2`
Where (a,b) is the coordinate for the center of our circle and r^2 is the radius squared.
Therefore, the center of our circle is at (2,3) and the radius is √16 = 4.