Question

I have missing work may someone help me with my math

Answer 1

2)

`w^2-3,\quad w=4`

When we say that w = 4, it means that we can rewrite the expression and instead of "w", we will put "4", so

`w^2-3\Rightarrow4^2-3`

Now we have a numerical expression to solve, we can easily solve it!

`\begin{gathered} 4^2-3 \\ \\ 4\cdot4-3 \\ \\ 16-3 \\ \\ 13 \end{gathered}`

Therefore, the final answer is

`4^2-3=13`

5)

Here we will do the same thing, the "hard" part is solving the numeric expression, it will be a little bit harder than the 2).

`3(6m-17),\quad m=5`

Again, repeat the same process, rewrite the expression, and instead of "m" you put "5"

`3(6m-17)\Rightarrow3(6\cdot5-17)`

Again, another expression to simplify, remember that we always solve what is inside ( ) first, and we have a multiplication inside ( ) so we must solve it first

`3(6\cdot5-17)=3(30-17)`

Now we solve the multiplication inside ( ) we can do the subctration

`3(30-17)=3\cdot(13)`

The last step is just to solve another multiplication

`3\cdot(13)=39`

Now we simplified everything we can have the final answer:

`3(6\cdot5-17)=39`

6)

Here we have a division, but it's similar with 5) and 2), we have

`(2a)/(3)+13,\quad a=15`

No secrets, repeat the process, but here, "a" will turn into "15", then

`(2a)/(3)+13\Rightarrow(2\cdot15)/(3)+13`

We can do the multiplication at the numerator of the fraction

`(2\cdot15)/(3)+13=(30)/(3)+13`

Now we can simplify the fraction, 30 divided by 3 is 10, then

`(30)/(3)+13=10+13`

Now just do the sum and it's done!

`10+13=23`

Hence the final answer is

`(2\cdot15)/(3)+13=23`

ANSWERS:

1) 43

2) 13

3) 67

4) 12

5) 39

6) 23