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21 votes
21 votes
Find the 26th term of an arithmetic sequence with \large a_1=-33 and \large d=4. a-130 b71 c-129 d67

User InnisBrendan
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1 Answer

19 votes
19 votes

Tn = a + ( n- 1 ) d

T 26 = -33 + ( 26 - 1 ) 4

T 26 = -33 + ( 25 x 4 )

= -33 + 100

= 67.............. Option D

User Vynz
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