Question

What is the number of particles, in moles, of430.11g of Calcium Chloride (CaCl₂)(Round any atomic mass from the periodic table toone decimal place.)

Answer 1

Step-by-step explanation:

First let's find the molar mass of CaCl2:

Ca = 40.1 g/mol

Cl = 35.5 g/mol

40.1 + (35.5*2) = 111.1 g/mol

So:

111.1 g ---- 1 mol

430.11 g ---- x mol

x = 3.871 mol

Answer: 3.9 moles