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Graph line 11) y=-x-14m =b =

User Victor Petrykin
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1 Answer

27 votes
27 votes

The general form of a linear equation is the slope-intercept form:


y=mx+b

Where m is the slope and b the intercept with the y-axis.

In the question we are asked to graph the line:


y=(1)/(4)x-1

We can identify that the slope is positive,


m=(1)/(4)

And the intercept with the y-axis is,


b=-1

Now we can graph the line, to graph the line you can first locate the intercept in the y-axis that is -1, after this, we use the slope. It is important for you to know that the slope is the change in y/ change in x, the slope we have is 1/4.

We locate in the -1 (y-intercept) and count 1 up (because the change in y is positive) and count 4 units to the right (because the change in x is positive), there we locate our other point (4,0), and with those two points located (0,-1) and (4,0) we draw the line.

Graph line 11) y=-x-14m =b =-example-1
User Ken Simon
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