Question

The locations, given in polar coordinates, for two planes approaching an airport are (4 mi, 12 degrees) and (3 mi, 73 degrees). Find the distance between the two planes.

Answer 1

d^2=(4cos12-3cos73)^2+(4sin12-3sin73)^2

d^2≈7.18593

d≈2.68mi (to nearest hundredth of a mile)

Answer 2

d^2=(4cos12-3cos73)^2+(4sin12-3sin73)^2

d^2≈7.18593

d≈2.68mi (to nearest hundredth of a mile)