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How do you completely factor 2x^3-8x^2-10x?
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How do you completely factor 2x^3-8x^2-10x?

User KindaTechy
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1 Answer

4 votes

1) First divide by 2


x^(3) -4 x^(2) -5x

2) And then factor

x(x-5)(x+1)

User Phillipwei
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