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2logvb(2y+2)=logvb16+2logvb(y-2)
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2logvb(2y+2)=logvb16+2logvb(y-2)

User Humayun Shabbir
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1 Answer

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Solve the equation by rewritting in exponential form using thge definition of a loagrithm and simplifying and your answer is
4 v ^ 2 (y+1)^2= v^3b^16 (y-2)^2
hope this helps

User Nazmin
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