Answer:
A.
f(x) = (-2/3)x + 10
B.
f(x) = 3x + 2
C.
f(x) = -3x - 12
Step-by-step explanation:
A.
For f(0) = 10 and m = -2/3
Put x = 0 and m = -2/3
10 = (-2/3)(0) + b
b = 10
f(x) = (-2/3)x + 10
B.
f(1) = 5 and m = 3
Put x = 1 and m = 3 to obtain b
5 = 3(1) + b
b = 5 - 3 = 2
f(x) = 3x + 2
C.
f(2) = 6 and f(4) = 0
Put x = 2 and f(x) = 6, also x = 4 and f(x) = 0
6 = 2m + b............................(1)
0 = 4m + b............................(2)
Solving (1) and (2) simultaneously
(2) - (1)
-6 = 2m
m = -6/2 = -3
Using m = -3 in (2)
0 = 4(-3) + b
b = -12
Therefore, we have m = -3 and b = -12
Putting these in the given equation
f(x) = -3x - 12