Question

Please help with this question:Solve for p.a = 6 + mp^2 A. p = a −6 / mB. p = ±a−6 / m−−−√C. p = ±a−6 √mD. p = a−6/2m

Answer 1

In order to solve for p from the given equation, you can follow these steps:

a = 6 + mp²

1. subtract 6 on both sides:

a - 6 = 6 - 6 + mp²

a - 6 = mp²

2. Divide both sides by m:

`\begin{gathered} (a-6)/(m)=(mp^2)/(m) \\ (a-6)/(m)=p^2 \end{gathered}`

3. Take the square root on both sides, dont forget to add the ±

`\begin{gathered} \sqrt{(a-6)/(m)}=√(p^2) \\ \pm\sqrt{(a-6)/(m)}=p \\ p=\pm\sqrt{(a-6)/(m)} \end{gathered}`

Then, the second option is the correct answer

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