Question

A coating of film  n=1.33

 on glass slabs  (n=1.6)  is  8.3× 10E −5  cm  thick. If white light is incident normally, which visible wavelengths are missing in the reflected light? 

Answer 1

the missing wavelengths would be those that give length of
`8.3 * 10-^(5)cm`

Step-by-step explanation:

Data:

Let the coating of the film be n = 1.33 on glass

The refractive index = 1.6

Thickness of the slab = 8.3 × 10⁻⁵ cm

Therefore, the angles are all determined from the normal

This gives:

`(sin\theta _(1) )/(sin\theta _(2) ) = (n_(1) )/(n_(2) )`

The relationship, known as Snell's law, can be used to evaluate the missing angles in the wavelength region.

Answer 2

We are given with
n1 = 1.33
n2 = 1.6
x = 8.3x10-5 cm

The angle of incident is normal, angle is 90
Using Snell's law
sin θ1 / sin θ2 = n2 / n1
Substitute the given values and solve for θ2