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Rewrite x^2+9 as a multiplication using complex numbers and the polynomial identity below u^2+v^2=(u+VI)(u-vi)
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2 votes
Rewrite x^2+9 as a multiplication using complex numbers and the polynomial identity below u^2+v^2=(u+VI)(u-vi)

User Soldieraman
by
9.0k points

2 Answers

3 votes
hello :
in : C
x²+9 = (x-3i)(x+3i) ..... i²= -1
User Knokio
by
8.4k points
4 votes

Answer:

(x + 3i) (x - 3i) is what I got.

I got 100% on my practice so it shouldn't be wrong. :)


User Vineet Shah
by
8.3k points
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